work: remove a statement with no effect

work_timeout() is a function, a statement like "(void)work_timeout;"
has no effect.

Signed-off-by: Guennadi Liakhovetski <guennadi.liakhovetski@linux.intel.com>
This commit is contained in:
Guennadi Liakhovetski 2021-04-29 15:01:49 +02:00 committed by Anas Nashif
commit d7a3752915

View file

@ -824,7 +824,6 @@ void k_work_init_delayable(struct k_work_delayable *dwork,
},
};
z_init_timeout(&dwork->timeout);
(void)work_timeout;
}
static inline int work_delayable_busy_get_locked(const struct k_work_delayable *dwork)