work: remove a statement with no effect
work_timeout() is a function, a statement like "(void)work_timeout;" has no effect. Signed-off-by: Guennadi Liakhovetski <guennadi.liakhovetski@linux.intel.com>
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@ -824,7 +824,6 @@ void k_work_init_delayable(struct k_work_delayable *dwork,
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},
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};
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z_init_timeout(&dwork->timeout);
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(void)work_timeout;
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}
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static inline int work_delayable_busy_get_locked(const struct k_work_delayable *dwork)
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