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arch: Fix assert logic for installing shared interrupt

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With this commit, it is now allowed to register any ISR and arg
combination for the same IRQ, except the case when the exact same
ISR-arg combination is already registered.

The previous assert logic had a restriction where the same ISR could not
be registered multiple times with different arguments.

Signed-off-by: Martin Åberg <martin.aberg@gaisler.com>
This commit is contained in:
Martin Åberg 2024-03-20 20:39:51 +01:00 • committed by Anas Nashif
commit 884a4e5a35
1 changed files with 2 additions and 2 deletions
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4
arch/common/shared_irq.c
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@ -92,8 +92,8 @@ void z_isr_install(unsigned int irq, void (*routine)(const void *),
for (i = 0; i < shared_entry->client_num; i++) { for (i = 0; i < shared_entry->client_num; i++) {
client = &shared_entry->clients[i]; client = &shared_entry->clients[i];
__ASSERT(client->isr != routine && client->arg != param, __ASSERT((client->isr == routine && client->arg == param) == false,
"trying to register duplicate ISR/arg pair"); "ISR/arg combination is already registered");
} }
shared_entry->clients[shared_entry->client_num].isr = routine; shared_entry->clients[shared_entry->client_num].isr = routine;